f(x)=(1+a(x-b)^-2)-1好像有问题?请确认

　　哦，是f(x）=（1+a(x-b)^-2)^-1,现在试试看可以不？或者你给我解一个类似的可以不？不会方法。。。

　　①x=1时，1/（1+1/（a(1-b)）²）=0.01x=3时，1/（1+1/（a(3-b)）²）=0.8>>s=solve('1/(1+1/(a*(1-b))^2)=0.01','1/(1+1/(a*(3-b))^2)=0.8');>>s.aans=-0.949748109237039396225531322171660.94974810923703939622553132217166-1.05025189076296060377446867782831.0502518907629606037744686778283>>s.bans=0.894178487381608105849672929518870.894178487381608105849672929518871.09569493033991088149209922237991.0956949303399108814920992223799②x=3时，c*ln(3)+d=0.8x=5时，c*ln(5)+d=1>>s=solve('c*log(3)+d=0.8','c*log(5)+d=1');>>s.cans=0.39152303779424353736713218093499>>s.dans=0.36986797938257529822904043154186